6y+1-3(-4y-3)=2(y-2)

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Solution for 6y+1-3(-4y-3)=2(y-2) equation: 



6y+1-3(-4y-3)=2(y-2)

We move all terms to the left:

6y+1-3(-4y-3)-(2(y-2))=0

We multiply parentheses

6y+12y-(2(y-2))+9+1=0



We calculate terms in parentheses: -(2(y-2)), so:

2(y-2)

We multiply parentheses

2y-4

Back to the equation:

-(2y-4)



We add all the numbers together, and all the variables

18y-(2y-4)+10=0

We get rid of parentheses

18y-2y+4+10=0

We add all the numbers together, and all the variables

16y+14=0

We move all terms containing y to the left, all other terms to the right

16y=-14

y=-14/16

y=-7/8

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