6y+1-3(4y-1)=4(y-2)

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Solution for 6y+1-3(4y-1)=4(y-2) equation:


Simplifying
6y + 1 + -3(4y + -1) = 4(y + -2)

Reorder the terms:
6y + 1 + -3(-1 + 4y) = 4(y + -2)
6y + 1 + (-1 * -3 + 4y * -3) = 4(y + -2)
6y + 1 + (3 + -12y) = 4(y + -2)

Reorder the terms:
1 + 3 + 6y + -12y = 4(y + -2)

Combine like terms: 1 + 3 = 4
4 + 6y + -12y = 4(y + -2)

Combine like terms: 6y + -12y = -6y
4 + -6y = 4(y + -2)

Reorder the terms:
4 + -6y = 4(-2 + y)
4 + -6y = (-2 * 4 + y * 4)
4 + -6y = (-8 + 4y)

Solving
4 + -6y = -8 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
4 + -6y + -4y = -8 + 4y + -4y

Combine like terms: -6y + -4y = -10y
4 + -10y = -8 + 4y + -4y

Combine like terms: 4y + -4y = 0
4 + -10y = -8 + 0
4 + -10y = -8

Add '-4' to each side of the equation.
4 + -4 + -10y = -8 + -4

Combine like terms: 4 + -4 = 0
0 + -10y = -8 + -4
-10y = -8 + -4

Combine like terms: -8 + -4 = -12
-10y = -12

Divide each side by '-10'.
y = 1.2

Simplifying
y = 1.2

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