6y+10=1+6(3y-4)

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Solution for 6y+10=1+6(3y-4) equation: 



6y+10=1+6(3y-4)

We move all terms to the left:

6y+10-(1+6(3y-4))=0



We calculate terms in parentheses: -(1+6(3y-4)), so:

1+6(3y-4)

determiningTheFunctionDomain
6(3y-4)+1

We multiply parentheses

18y-24+1

We add all the numbers together, and all the variables

18y-23

Back to the equation:

-(18y-23)



We get rid of parentheses

6y-18y+23+10=0

We add all the numbers together, and all the variables

-12y+33=0

We move all terms containing y to the left, all other terms to the right

-12y=-33

y=-33/-12

y=2+3/4

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