6y+12=2-(y+10)

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Solution for 6y+12=2-(y+10) equation:



6y+12=2-(y+10)
We move all terms to the left:
6y+12-(2-(y+10))=0
We calculate terms in parentheses: -(2-(y+10)), so:
2-(y+10)
determiningTheFunctionDomain -(y+10)+2
We get rid of parentheses
-y-10+2
We add all the numbers together, and all the variables
-1y-8
Back to the equation:
-(-1y-8)
We get rid of parentheses
6y+1y+8+12=0
We add all the numbers together, and all the variables
7y+20=0
We move all terms containing y to the left, all other terms to the right
7y=-20
y=-20/7
y=-2+6/7

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