6y+12=2-(y+10)

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Solution for 6y+12=2-(y+10) equation: 



6y+12=2-(y+10)

We move all terms to the left:

6y+12-(2-(y+10))=0



We calculate terms in parentheses: -(2-(y+10)), so:

2-(y+10)

determiningTheFunctionDomain
-(y+10)+2

We get rid of parentheses

-y-10+2

We add all the numbers together, and all the variables

-1y-8

Back to the equation:

-(-1y-8)



We get rid of parentheses

6y+1y+8+12=0

We add all the numbers together, and all the variables

7y+20=0

We move all terms containing y to the left, all other terms to the right

7y=-20

y=-20/7

y=-2+6/7

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