6y+1=3(2y-1/3)

Solution for 6y+1=3(2y-1/3) equation:

6y+1=3(2y-1/3)

We move all terms to the left:

6y+1-(3(2y-1/3))=0

We add all the numbers together, and all the variables

6y-(3(+2y-1/3))+1=0

We multiply all the terms by the denominator


6y*3))-(3(+2y-1+1*3))=0

We add all the numbers together, and all the variables

6y*3))-(3(2y+2))=0

We add all the numbers together, and all the variables

6y*3))-(3(2y=0

Wy multiply elements

18y^2=0

a = 18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·18·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{36}=0$