6y+2(5y-9)=5(3y-4)+11

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Solution for 6y+2(5y-9)=5(3y-4)+11 equation: 



6y+2(5y-9)=5(3y-4)+11

We move all terms to the left:

6y+2(5y-9)-(5(3y-4)+11)=0

We multiply parentheses

6y+10y-(5(3y-4)+11)-18=0



We calculate terms in parentheses: -(5(3y-4)+11), so:

5(3y-4)+11

We multiply parentheses

15y-20+11

We add all the numbers together, and all the variables

15y-9

Back to the equation:

-(15y-9)



We add all the numbers together, and all the variables

16y-(15y-9)-18=0

We get rid of parentheses

16y-15y+9-18=0

We add all the numbers together, and all the variables

y-9=0

We move all terms containing y to the left, all other terms to the right

y=9

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