6y+2(y-2)=5(y+1)-4

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Solution for 6y+2(y-2)=5(y+1)-4 equation:



6y+2(y-2)=5(y+1)-4
We move all terms to the left:
6y+2(y-2)-(5(y+1)-4)=0
We multiply parentheses
6y+2y-(5(y+1)-4)-4=0
We calculate terms in parentheses: -(5(y+1)-4), so:
5(y+1)-4
We multiply parentheses
5y+5-4
We add all the numbers together, and all the variables
5y+1
Back to the equation:
-(5y+1)
We add all the numbers together, and all the variables
8y-(5y+1)-4=0
We get rid of parentheses
8y-5y-1-4=0
We add all the numbers together, and all the variables
3y-5=0
We move all terms containing y to the left, all other terms to the right
3y=5
y=5/3
y=1+2/3

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