6y+2(y-4)=2=

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Solution for 6y+2(y-4)=2= equation: 



6y+2(y-4)=2=

We move all terms to the left:

6y+2(y-4)-(2)=0

We multiply parentheses

6y+2y-8-2=0

We add all the numbers together, and all the variables

8y-10=0

We move all terms containing y to the left, all other terms to the right

8y=10

y=10/8

y=1+1/4

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