6y+28=-2(y-2)

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Solution for 6y+28=-2(y-2) equation: 



6y+28=-2(y-2)

We move all terms to the left:

6y+28-(-2(y-2))=0



We calculate terms in parentheses: -(-2(y-2)), so:

-2(y-2)

We multiply parentheses

-2y+4

Back to the equation:

-(-2y+4)



We get rid of parentheses

6y+2y-4+28=0

We add all the numbers together, and all the variables

8y+24=0

We move all terms containing y to the left, all other terms to the right

8y=-24

y=-24/8

y=-3

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