6y+3(1/3y-4)=7y+2y+12

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Solution for 6y+3(1/3y-4)=7y+2y+12 equation: 



6y+3(1/3y-4)=7y+2y+12

We move all terms to the left:

6y+3(1/3y-4)-(7y+2y+12)=0



Domain of the equation: 3y-4)!=0

y∈R



We add all the numbers together, and all the variables

6y+3(1/3y-4)-(9y+12)=0

We multiply parentheses

6y+3y-(9y+12)-12=0

We get rid of parentheses

6y+3y-9y-12-12=0

We add all the numbers together, and all the variables

-24!=0

There is no solution for this equation

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