6y+3(y-7)=33

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Solution for 6y+3(y-7)=33 equation:



6y+3(y-7)=33
We move all terms to the left:
6y+3(y-7)-(33)=0
We multiply parentheses
6y+3y-21-33=0
We add all the numbers together, and all the variables
9y-54=0
We move all terms containing y to the left, all other terms to the right
9y=54
y=54/9
y=6

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