6y+4(2y-2)=3(2y+4)

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Solution for 6y+4(2y-2)=3(2y+4) equation: 



6y+4(2y-2)=3(2y+4)

We move all terms to the left:

6y+4(2y-2)-(3(2y+4))=0

We multiply parentheses

6y+8y-(3(2y+4))-8=0



We calculate terms in parentheses: -(3(2y+4)), so:

3(2y+4)

We multiply parentheses

6y+12

Back to the equation:

-(6y+12)



We add all the numbers together, and all the variables

14y-(6y+12)-8=0

We get rid of parentheses

14y-6y-12-8=0

We add all the numbers together, and all the variables

8y-20=0

We move all terms containing y to the left, all other terms to the right

8y=20

y=20/8

y=2+1/2

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