6y+42=-9(y-3)

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Solution for 6y+42=-9(y-3) equation: 



6y+42=-9(y-3)

We move all terms to the left:

6y+42-(-9(y-3))=0



We calculate terms in parentheses: -(-9(y-3)), so:

-9(y-3)

We multiply parentheses

-9y+27

Back to the equation:

-(-9y+27)



We get rid of parentheses

6y+9y-27+42=0

We add all the numbers together, and all the variables

15y+15=0

We move all terms containing y to the left, all other terms to the right

15y=-15

y=-15/15

y=-1

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