6y+42=9(y-3)

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Solution for 6y+42=9(y-3) equation: 



6y+42=9(y-3)

We move all terms to the left:

6y+42-(9(y-3))=0



We calculate terms in parentheses: -(9(y-3)), so:

9(y-3)

We multiply parentheses

9y-27

Back to the equation:

-(9y-27)



We get rid of parentheses

6y-9y+27+42=0

We add all the numbers together, and all the variables

-3y+69=0

We move all terms containing y to the left, all other terms to the right

-3y=-69

y=-69/-3

y=+23

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