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6y+6y*3y=12
We move all terms to the left:
6y+6y*3y-(12)=0
Wy multiply elements
18y^2+6y-12=0
a = 18; b = 6; c = -12;
Δ = b2-4ac
Δ = 62-4·18·(-12)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-30}{2*18}=\frac{-36}{36} =-1 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+30}{2*18}=\frac{24}{36} =2/3 $
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