6y+7+3y=3(3y-2)+13

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Solution for 6y+7+3y=3(3y-2)+13 equation: 


Simplifying
6y + 7 + 3y = 3(3y + -2) + 13

Reorder the terms:
7 + 6y + 3y = 3(3y + -2) + 13

Combine like terms: 6y + 3y = 9y
7 + 9y = 3(3y + -2) + 13

Reorder the terms:
7 + 9y = 3(-2 + 3y) + 13
7 + 9y = (-2 * 3 + 3y * 3) + 13
7 + 9y = (-6 + 9y) + 13

Reorder the terms:
7 + 9y = -6 + 13 + 9y

Combine like terms: -6 + 13 = 7
7 + 9y = 7 + 9y

Add '-7' to each side of the equation.
7 + -7 + 9y = 7 + -7 + 9y

Combine like terms: 7 + -7 = 0
0 + 9y = 7 + -7 + 9y
9y = 7 + -7 + 9y

Combine like terms: 7 + -7 = 0
9y = 0 + 9y
9y = 9y

Add '-9y' to each side of the equation.
9y + -9y = 9y + -9y

Combine like terms: 9y + -9y = 0
0 = 9y + -9y

Combine like terms: 9y + -9y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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