6y+7=3+2(2y-4)

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Solution for 6y+7=3+2(2y-4) equation:



6y+7=3+2(2y-4)
We move all terms to the left:
6y+7-(3+2(2y-4))=0
We calculate terms in parentheses: -(3+2(2y-4)), so:
3+2(2y-4)
determiningTheFunctionDomain 2(2y-4)+3
We multiply parentheses
4y-8+3
We add all the numbers together, and all the variables
4y-5
Back to the equation:
-(4y-5)
We get rid of parentheses
6y-4y+5+7=0
We add all the numbers together, and all the variables
2y+12=0
We move all terms containing y to the left, all other terms to the right
2y=-12
y=-12/2
y=-6

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