6y+8(y-3)=12y+10

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Solution for 6y+8(y-3)=12y+10 equation: 



6y+8(y-3)=12y+10

We move all terms to the left:

6y+8(y-3)-(12y+10)=0

We multiply parentheses

6y+8y-(12y+10)-24=0

We get rid of parentheses

6y+8y-12y-10-24=0

We add all the numbers together, and all the variables

2y-34=0

We move all terms containing y to the left, all other terms to the right

2y=34

y=34/2

y=17

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