6y+8+2y=3(y-12)

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Solution for 6y+8+2y=3(y-12) equation: 



6y+8+2y=3(y-12)

We move all terms to the left:

6y+8+2y-(3(y-12))=0

We add all the numbers together, and all the variables

8y-(3(y-12))+8=0



We calculate terms in parentheses: -(3(y-12)), so:

3(y-12)

We multiply parentheses

3y-36

Back to the equation:

-(3y-36)



We get rid of parentheses

8y-3y+36+8=0

We add all the numbers together, and all the variables

5y+44=0

We move all terms containing y to the left, all other terms to the right

5y=-44

y=-44/5

y=-8+4/5

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