6y+9-3(-4-1)=4(y-1)

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Solution for 6y+9-3(-4-1)=4(y-1) equation: 



6y+9-3(-4-1)=4(y-1)

We move all terms to the left:

6y+9-3(-4-1)-(4(y-1))=0

We add all the numbers together, and all the variables

6y-(4(y-1))+9-3(-5)=0

We add all the numbers together, and all the variables

6y-(4(y-1))+24=0



We calculate terms in parentheses: -(4(y-1)), so:

4(y-1)

We multiply parentheses

4y-4

Back to the equation:

-(4y-4)



We get rid of parentheses

6y-4y+4+24=0

We add all the numbers together, and all the variables

2y+28=0

We move all terms containing y to the left, all other terms to the right

2y=-28

y=-28/2

y=-14

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