6y-15=3(10y-40)

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Solution for 6y-15=3(10y-40) equation: 



6y-15=3(10y-40)

We move all terms to the left:

6y-15-(3(10y-40))=0



We calculate terms in parentheses: -(3(10y-40)), so:

3(10y-40)

We multiply parentheses

30y-120

Back to the equation:

-(30y-120)



We get rid of parentheses

6y-30y+120-15=0

We add all the numbers together, and all the variables

-24y+105=0

We move all terms containing y to the left, all other terms to the right

-24y=-105

y=-105/-24

y=4+3/8

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