6y-18y+34=2(y+3)

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Solution for 6y-18y+34=2(y+3) equation:



6y-18y+34=2(y+3)
We move all terms to the left:
6y-18y+34-(2(y+3))=0
We add all the numbers together, and all the variables
-12y-(2(y+3))+34=0
We calculate terms in parentheses: -(2(y+3)), so:
2(y+3)
We multiply parentheses
2y+6
Back to the equation:
-(2y+6)
We get rid of parentheses
-12y-2y-6+34=0
We add all the numbers together, and all the variables
-14y+28=0
We move all terms containing y to the left, all other terms to the right
-14y=-28
y=-28/-14
y=+2

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