6y-2(2+y)=3(y+2)

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Solution for 6y-2(2+y)=3(y+2) equation: 



6y-2(2+y)=3(y+2)

We move all terms to the left:

6y-2(2+y)-(3(y+2))=0

We add all the numbers together, and all the variables

6y-2(y+2)-(3(y+2))=0

We multiply parentheses

6y-2y-(3(y+2))-4=0



We calculate terms in parentheses: -(3(y+2)), so:

3(y+2)

We multiply parentheses

3y+6

Back to the equation:

-(3y+6)



We add all the numbers together, and all the variables

4y-(3y+6)-4=0

We get rid of parentheses

4y-3y-6-4=0

We add all the numbers together, and all the variables

y-10=0

We move all terms containing y to the left, all other terms to the right

y=10

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