6y-2(2-y)=4(2y-1)

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Solution for 6y-2(2-y)=4(2y-1) equation: 



6y-2(2-y)=4(2y-1)

We move all terms to the left:

6y-2(2-y)-(4(2y-1))=0

We add all the numbers together, and all the variables

6y-2(-1y+2)-(4(2y-1))=0

We multiply parentheses

6y+2y-(4(2y-1))-4=0



We calculate terms in parentheses: -(4(2y-1)), so:

4(2y-1)

We multiply parentheses

8y-4

Back to the equation:

-(8y-4)



We add all the numbers together, and all the variables

8y-(8y-4)-4=0

We get rid of parentheses

8y-8y+4-4=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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