6y-2-3(y-4)=16

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Solution for 6y-2-3(y-4)=16 equation: 



6y-2-3(y-4)=16

We move all terms to the left:

6y-2-3(y-4)-(16)=0

We add all the numbers together, and all the variables

6y-3(y-4)-18=0

We multiply parentheses

6y-3y+12-18=0

We add all the numbers together, and all the variables

3y-6=0

We move all terms containing y to the left, all other terms to the right

3y=6

y=6/3

y=2

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