6y-3(2y+3)=2(1-2y)

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Solution for 6y-3(2y+3)=2(1-2y) equation: 



6y-3(2y+3)=2(1-2y)

We move all terms to the left:

6y-3(2y+3)-(2(1-2y))=0

We add all the numbers together, and all the variables

6y-3(2y+3)-(2(-2y+1))=0

We multiply parentheses

6y-6y-(2(-2y+1))-9=0



We calculate terms in parentheses: -(2(-2y+1)), so:

2(-2y+1)

We multiply parentheses

-4y+2

Back to the equation:

-(-4y+2)



We add all the numbers together, and all the variables

-(-4y+2)-9=0

We get rid of parentheses

4y-2-9=0

We add all the numbers together, and all the variables

4y-11=0

We move all terms containing y to the left, all other terms to the right

4y=11

y=11/4

y=2+3/4

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