6y-3(y+1)=2(y+3)+3

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Solution for 6y-3(y+1)=2(y+3)+3 equation: 



6y-3(y+1)=2(y+3)+3

We move all terms to the left:

6y-3(y+1)-(2(y+3)+3)=0

We multiply parentheses

6y-3y-(2(y+3)+3)-3=0



We calculate terms in parentheses: -(2(y+3)+3), so:

2(y+3)+3

We multiply parentheses

2y+6+3

We add all the numbers together, and all the variables

2y+9

Back to the equation:

-(2y+9)



We add all the numbers together, and all the variables

3y-(2y+9)-3=0

We get rid of parentheses

3y-2y-9-3=0

We add all the numbers together, and all the variables

y-12=0

We move all terms containing y to the left, all other terms to the right

y=12

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