6y-3=2(3y+1)-4

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Solution for 6y-3=2(3y+1)-4 equation: 



6y-3=2(3y+1)-4

We move all terms to the left:

6y-3-(2(3y+1)-4)=0



We calculate terms in parentheses: -(2(3y+1)-4), so:

2(3y+1)-4

We multiply parentheses

6y+2-4

We add all the numbers together, and all the variables

6y-2

Back to the equation:

-(6y-2)



We get rid of parentheses

6y-6y+2-3=0

We add all the numbers together, and all the variables

-1!=0

There is no solution for this equation

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