6y-3y+12=5(7y-4)

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Solution for 6y-3y+12=5(7y-4) equation: 



6y-3y+12=5(7y-4)

We move all terms to the left:

6y-3y+12-(5(7y-4))=0

We add all the numbers together, and all the variables

3y-(5(7y-4))+12=0



We calculate terms in parentheses: -(5(7y-4)), so:

5(7y-4)

We multiply parentheses

35y-20

Back to the equation:

-(35y-20)



We get rid of parentheses

3y-35y+20+12=0

We add all the numbers together, and all the variables

-32y+32=0

We move all terms containing y to the left, all other terms to the right

-32y=-32

y=-32/-32

y=1

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