6y-4(3-2y)=5(y-4)-10

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Solution for 6y-4(3-2y)=5(y-4)-10 equation:



6y-4(3-2y)=5(y-4)-10
We move all terms to the left:
6y-4(3-2y)-(5(y-4)-10)=0
We add all the numbers together, and all the variables
6y-4(-2y+3)-(5(y-4)-10)=0
We multiply parentheses
6y+8y-(5(y-4)-10)-12=0
We calculate terms in parentheses: -(5(y-4)-10), so:
5(y-4)-10
We multiply parentheses
5y-20-10
We add all the numbers together, and all the variables
5y-30
Back to the equation:
-(5y-30)
We add all the numbers together, and all the variables
14y-(5y-30)-12=0
We get rid of parentheses
14y-5y+30-12=0
We add all the numbers together, and all the variables
9y+18=0
We move all terms containing y to the left, all other terms to the right
9y=-18
y=-18/9
y=-2

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