6y-4(3-2y)=5(y-4)-10

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Solution for 6y-4(3-2y)=5(y-4)-10 equation: 



6y-4(3-2y)=5(y-4)-10

We move all terms to the left:

6y-4(3-2y)-(5(y-4)-10)=0

We add all the numbers together, and all the variables

6y-4(-2y+3)-(5(y-4)-10)=0

We multiply parentheses

6y+8y-(5(y-4)-10)-12=0



We calculate terms in parentheses: -(5(y-4)-10), so:

5(y-4)-10

We multiply parentheses

5y-20-10

We add all the numbers together, and all the variables

5y-30

Back to the equation:

-(5y-30)



We add all the numbers together, and all the variables

14y-(5y-30)-12=0

We get rid of parentheses

14y-5y+30-12=0

We add all the numbers together, and all the variables

9y+18=0

We move all terms containing y to the left, all other terms to the right

9y=-18

y=-18/9

y=-2

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