6y-4+1=3(2y-1)

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Solution for 6y-4+1=3(2y-1) equation: 



6y-4+1=3(2y-1)

We move all terms to the left:

6y-4+1-(3(2y-1))=0

We add all the numbers together, and all the variables

6y-(3(2y-1))-3=0



We calculate terms in parentheses: -(3(2y-1)), so:

3(2y-1)

We multiply parentheses

6y-3

Back to the equation:

-(6y-3)



We get rid of parentheses

6y-6y+3-3=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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