6y-42+10y=8y-3

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Solution for 6y-42+10y=8y-3 equation: 



6y-42+10y=8y-3

We move all terms to the left:

6y-42+10y-(8y-3)=0

We add all the numbers together, and all the variables

16y-(8y-3)-42=0

We get rid of parentheses

16y-8y+3-42=0

We add all the numbers together, and all the variables

8y-39=0

We move all terms containing y to the left, all other terms to the right

8y=39

y=39/8

y=4+7/8

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