6y-5(1+2y)=57+2(1-y)

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Solution for 6y-5(1+2y)=57+2(1-y) equation: 



6y-5(1+2y)=57+2(1-y)

We move all terms to the left:

6y-5(1+2y)-(57+2(1-y))=0

We add all the numbers together, and all the variables

6y-5(2y+1)-(57+2(-1y+1))=0

We multiply parentheses

6y-10y-(57+2(-1y+1))-5=0



We calculate terms in parentheses: -(57+2(-1y+1)), so:

57+2(-1y+1)

determiningTheFunctionDomain
2(-1y+1)+57

We multiply parentheses

-2y+2+57

We add all the numbers together, and all the variables

-2y+59

Back to the equation:

-(-2y+59)



We add all the numbers together, and all the variables

-4y-(-2y+59)-5=0

We get rid of parentheses

-4y+2y-59-5=0

We add all the numbers together, and all the variables

-2y-64=0

We move all terms containing y to the left, all other terms to the right

-2y=64

y=64/-2

y=-32

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