6y-5(y-3)+4=19

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Solution for 6y-5(y-3)+4=19 equation: 



6y-5(y-3)+4=19

We move all terms to the left:

6y-5(y-3)+4-(19)=0

We add all the numbers together, and all the variables

6y-5(y-3)-15=0

We multiply parentheses

6y-5y+15-15=0

We add all the numbers together, and all the variables

y=0

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