6y-6+2(3y+3)=-2(y+6)

Solution for 6y-6+2(3y+3)=-2(y+6) equation:

6y-6+2(3y+3)=-2(y+6)

We move all terms to the left:

6y-6+2(3y+3)-(-2(y+6))=0

We multiply parentheses

6y+6y-(-2(y+6))+6-6=0


We calculate terms in parentheses: -(-2(y+6)), so:

-2(y+6)

We multiply parentheses

-2y-12

Back to the equation:

-(-2y-12)


We add all the numbers together, and all the variables

12y-(-2y-12)=0

We get rid of parentheses

12y+2y+12=0

We add all the numbers together, and all the variables

14y+12=0

We move all terms containing y to the left, all other terms to the right

14y=-12

y=-12/14

y=-6/7