6y-6+2y=2(4y-3)

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Solution for 6y-6+2y=2(4y-3) equation: 



6y-6+2y=2(4y-3)

We move all terms to the left:

6y-6+2y-(2(4y-3))=0

We add all the numbers together, and all the variables

8y-(2(4y-3))-6=0



We calculate terms in parentheses: -(2(4y-3)), so:

2(4y-3)

We multiply parentheses

8y-6

Back to the equation:

-(8y-6)



We get rid of parentheses

8y-8y+6-6=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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