6y-7+2(3y+5)=-2(y+2)

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Solution for 6y-7+2(3y+5)=-2(y+2) equation:



6y-7+2(3y+5)=-2(y+2)
We move all terms to the left:
6y-7+2(3y+5)-(-2(y+2))=0
We multiply parentheses
6y+6y-(-2(y+2))+10-7=0
We calculate terms in parentheses: -(-2(y+2)), so:
-2(y+2)
We multiply parentheses
-2y-4
Back to the equation:
-(-2y-4)
We add all the numbers together, and all the variables
12y-(-2y-4)+3=0
We get rid of parentheses
12y+2y+4+3=0
We add all the numbers together, and all the variables
14y+7=0
We move all terms containing y to the left, all other terms to the right
14y=-7
y=-7/14
y=-1/2

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