6y-8+2(2y+5)=-2(y+4)

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Solution for 6y-8+2(2y+5)=-2(y+4) equation: 



6y-8+2(2y+5)=-2(y+4)

We move all terms to the left:

6y-8+2(2y+5)-(-2(y+4))=0

We multiply parentheses

6y+4y-(-2(y+4))+10-8=0



We calculate terms in parentheses: -(-2(y+4)), so:

-2(y+4)

We multiply parentheses

-2y-8

Back to the equation:

-(-2y-8)



We add all the numbers together, and all the variables

10y-(-2y-8)+2=0

We get rid of parentheses

10y+2y+8+2=0

We add all the numbers together, and all the variables

12y+10=0

We move all terms containing y to the left, all other terms to the right

12y=-10

y=-10/12

y=-5/6

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