6y-9+2(3y+3)=-6(y+3)

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Solution for 6y-9+2(3y+3)=-6(y+3) equation: 



6y-9+2(3y+3)=-6(y+3)

We move all terms to the left:

6y-9+2(3y+3)-(-6(y+3))=0

We multiply parentheses

6y+6y-(-6(y+3))+6-9=0



We calculate terms in parentheses: -(-6(y+3)), so:

-6(y+3)

We multiply parentheses

-6y-18

Back to the equation:

-(-6y-18)



We add all the numbers together, and all the variables

12y-(-6y-18)-3=0

We get rid of parentheses

12y+6y+18-3=0

We add all the numbers together, and all the variables

18y+15=0

We move all terms containing y to the left, all other terms to the right

18y=-15

y=-15/18

y=-5/6

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