6y-9+3(3y+5)=-3(y+2)

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Solution for 6y-9+3(3y+5)=-3(y+2) equation: 



6y-9+3(3y+5)=-3(y+2)

We move all terms to the left:

6y-9+3(3y+5)-(-3(y+2))=0

We multiply parentheses

6y+9y-(-3(y+2))+15-9=0



We calculate terms in parentheses: -(-3(y+2)), so:

-3(y+2)

We multiply parentheses

-3y-6

Back to the equation:

-(-3y-6)



We add all the numbers together, and all the variables

15y-(-3y-6)+6=0

We get rid of parentheses

15y+3y+6+6=0

We add all the numbers together, and all the variables

18y+12=0

We move all terms containing y to the left, all other terms to the right

18y=-12

y=-12/18

y=-2/3

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