6y/y-8+3=y-40/y+8

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Solution for 6y/y-8+3=y-40/y+8 equation:


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

(6*y)/y-8+3 = y-(40/y)+8 // - y-(40/y)+8

40/y-y+(6*y)/y-8-8+3 = 0

40*y^-1-1*y^1-7*y^0 = 0

(40*y^0-1*y^2-7*y^1)/(y^1) = 0 // * y^2

y^1*(40*y^0-1*y^2-7*y^1) = 0

y^1

40-y^2-7*y = 0

40-y^2-7*y = 0

DELTA = (-7)^2-(-1*4*40)

DELTA = 209

DELTA > 0

y = (209^(1/2)+7)/(-1*2) or y = (7-209^(1/2))/(-1*2)

y = (209^(1/2)+7)/(-2) or y = (7-209^(1/2))/(-2)

y in { (209^(1/2)+7)/(-2), (7-209^(1/2))/(-2)}

y in { (209^(1/2)+7)/(-2), (7-209^(1/2))/(-2) }

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