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6y^2+43y+7=0
a = 6; b = 43; c = +7;
Δ = b2-4ac
Δ = 432-4·6·7
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-41}{2*6}=\frac{-84}{12} =-7 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+41}{2*6}=\frac{-2}{12} =-1/6 $
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