6y2-36y+50=0

Solution for 6y2-36y+50=0 equation:

6y^2-36y+50=0

a = 6; b = -36; c = +50;
Δ = b2-4ac
Δ = -362-4·6·50
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-4\sqrt{6}}{2*6}=\frac{36-4\sqrt{6}}{12}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+4\sqrt{6}}{2*6}=\frac{36+4\sqrt{6}}{12}
$