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6y^2-37y+35=0
a = 6; b = -37; c = +35;
Δ = b2-4ac
Δ = -372-4·6·35
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-23}{2*6}=\frac{14}{12} =1+1/6 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+23}{2*6}=\frac{60}{12} =5 $
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