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6y^2=50
We move all terms to the left:
6y^2-(50)=0
a = 6; b = 0; c = -50;
Δ = b2-4ac
Δ = 02-4·6·(-50)
Δ = 1200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1200}=\sqrt{400*3}=\sqrt{400}*\sqrt{3}=20\sqrt{3}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{3}}{2*6}=\frac{0-20\sqrt{3}}{12} =-\frac{20\sqrt{3}}{12} =-\frac{5\sqrt{3}}{3} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{3}}{2*6}=\frac{0+20\sqrt{3}}{12} =\frac{20\sqrt{3}}{12} =\frac{5\sqrt{3}}{3} $
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