6y=(2y+12)=29

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Solution for 6y=(2y+12)=29 equation: 



6y=(2y+12)=29

We move all terms to the left:

6y-((2y+12))=0



We calculate terms in parentheses: -((2y+12)), so:

(2y+12)

We get rid of parentheses

2y+12

Back to the equation:

-(2y+12)



We get rid of parentheses

6y-2y-12=0

We add all the numbers together, and all the variables

4y-12=0

We move all terms containing y to the left, all other terms to the right

4y=12

y=12/4

y=3

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