6y=3(y+4)+y

Solution for 6y=3(y+4)+y equation:

6y=3(y+4)+y

We move all terms to the left:

6y-(3(y+4)+y)=0


We calculate terms in parentheses: -(3(y+4)+y), so:

3(y+4)+y

We add all the numbers together, and all the variables

y+3(y+4)

We multiply parentheses

y+3y+12

We add all the numbers together, and all the variables

4y+12

Back to the equation:

-(4y+12)


We get rid of parentheses

6y-4y-12=0

We add all the numbers together, and all the variables

2y-12=0

We move all terms containing y to the left, all other terms to the right

2y=12

y=12/2

y=6