6y=36,y2/2

Solution for 6y=36,y2/2 equation:

6y=36.y^2/2

We move all terms to the left:

6y-(36.y^2/2)=0

We get rid of parentheses

-36.y^2/2+6y=0

We multiply all the terms by the denominator


-36.y^2+6y*2=0

We add all the numbers together, and all the variables

-36y^2+6y*2=0

Wy multiply elements

-36y^2+12y=0

a = -36; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-36)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-36}=\frac{-24}{-72}
=1/3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-36}=\frac{0}{-72}
=0
$