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6y=5y(y+13)
We move all terms to the left:
6y-(5y(y+13))=0
We calculate terms in parentheses: -(5y(y+13)), so:We get rid of parentheses
5y(y+13)
We multiply parentheses
5y^2+65y
Back to the equation:
-(5y^2+65y)
-5y^2+6y-65y=0
We add all the numbers together, and all the variables
-5y^2-59y=0
a = -5; b = -59; c = 0;
Δ = b2-4ac
Δ = -592-4·(-5)·0
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3481}=59$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-59)-59}{2*-5}=\frac{0}{-10} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-59)+59}{2*-5}=\frac{118}{-10} =-11+4/5 $
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