6z+11=6(z+2)-1

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Solution for 6z+11=6(z+2)-1 equation: 



6z+11=6(z+2)-1

We move all terms to the left:

6z+11-(6(z+2)-1)=0



We calculate terms in parentheses: -(6(z+2)-1), so:

6(z+2)-1

We multiply parentheses

6z+12-1

We add all the numbers together, and all the variables

6z+11

Back to the equation:

-(6z+11)



We get rid of parentheses

6z-6z-11+11=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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